A gas contains 1% mol of ethane. Is in contact with H2O @20 C degrees . And 20 atm. Using Henry's law, calculate the mole fraction if dissolve ethanel.
YAPsys=XAHA
The problem ask the mole fraction of the liquid
Information given
YA=0.01 mol
Psys=20 atm
HA=2.63x10^4 atm (see tables ethane at 20º C)
What we need:
XA=?
Solving the ecuation for XA:
XA=YAPsys/HA
XA=(0.01mol*20atm)/2.63x10^4atm=7.6045x10^-6 mol
YAPsys=XAHA
The problem ask the mole fraction of the liquid
Information given
YA=0.01 mol
Psys=20 atm
HA=2.63x10^4 atm (see tables ethane at 20º C)
What we need:
XA=?
Solving the ecuation for XA:
XA=YAPsys/HA
XA=(0.01mol*20atm)/2.63x10^4atm=7.6045x10^-6 mol